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Some
people jump out of perfectly good airplanes on purpose. These parachute
jumpers experience a unique sensation during free fall, before their
parachutes open. For many parachutists, this is why they jump. During free fall, the parachutist reaches a terminal velocity (a constant velocity) of somewhere between 120 and
180 miles per hour. (If you go feet first, you go faster than if you lie on
your back.) When the rip cord is pulled, there is some acceleration, then a
gentle float back to earth.
But what forces act on the
parachutist and why is a terminal velocity reached? Gravity and air friction both exert forces on a parachutist. Gravity
is constant, but air friction changes with velocity. If you hold your hand
outside a car, no air friction acts on your hand if the car is standing still.
But if the car is moving at 55 miles per hour, then there is a large force.
This shows that this force is dependent on velocity. Actually, air friction is
related to the square of the velocity, the size of the object, and a constant.
This is shown by the equation:
f
= kAv2
where f is the frictional force, k
is a constant related to the surface over which the air passes, A is the cross-sectional
area of the object, and v2 is the velocity squared.
"Cross-sectional area"
may be a new idea. Looking up at a parachutist, if she were falling feet
first, you would see only a very small area of the sky covered. If she were
falling on her back, she would cover a larger part of the sky. We could say
that when she is on her back, she presents a larger cross-sectional area.
Therefore, from the standpoint of our equation, the frictional force would be
greater.
The frictional force becomes
greater as the velocity increases, but the gravitational force remains
constant. Acceleration is related to the net force; i.e., the sum of the
frictional force and the gravitational force. As the frictional force
increases, the net force decreases. As the parachutist goes faster and faster,
the net force becomes smaller and smaller, so the acceleration becomes smaller
and smaller.
With a smaller acceleration, there
is a smaller change in velocity. The frictional force will not increase much
either, so the net force approaches zero, but it will never get there. It will
never get to zero for the same reason that a frog will never get out of a well
if it keeps jumping half the remaining distance; the closer it gets, the
smaller the "change" becomes. And the same is true of the frictional
force. Eventually, the parachutist
must pull the rip cord and then things are quite different. What forces does
the chute cause? Because the parachute increases the jumper's cross-sectional
area, it will provide a larger frictional force at a given velocity (f = kAv2).
This force opposes motion, so it is directed upward; it will decrease the
downward velocity. Stating this properly, a positive acceleration decreases
the negative velocity. Initially, the upward force is very great, so the net
force is upward. But as the parachutist slows down, the frictional force
decreases until it approximately equals the force of gravity, and a new
terminal velocity is reached. The terminal velocity is smaller because there
is a larger cross-sectional area. Our parachutist will continue at this
constant velocity until she hits the ground, which exerts an upward force on
her and stops her.
Initially the velocity is zero but it becomes more negative
(because it is downward) until a terminal velocity is reached. As
terminal velocity is reached, the change in velocity in a given amount of time
grows smaller and smaller. After the rip cord is pulled and the parachute
opens, the velocity becomes less negative but still remains negative. After a
brief moment, the velocity again approaches its terminal point and stays
that way until the ground is hit and the velocity becomes zero.
The
graph of acceleration versus time is also interesting. Initially, the only
force acting on our parachutist is gravity, which has a downward pull. This is
a negative force and provides negative acceleration, but as the net force
becomes smaller, the acceleration grows smaller. At terminal velocity, the acceleration equals zero.
After the chute opens, a net upward force causes a positive acceleration which
initially is great and then becomes small. A terminal velocity is again
reached and the acceleration is again zero. Finally, the ground causes
alarge upward force and upward acceleration which stops the parachutist. (See
Figure 8.2.) As you work with these graphs, think about how the jump would
feel. What forces would you experience in a parachute jump? Perhaps you
would enjoy the experience, and perhaps you would not?
Parachutes
and Terminal Velocity – A Review
I.
Parachutist jumps from plane.
II.
Person accelerates (gravitational force is count)
A. Acceleration
related to net force
1. net force = sum of frictional and gravitational forces
2. as frictional force increases net force decreases
3. as cross-sectional area increases frictional forces increase
B. As person goes faster, net force is smaller and acceleration
C. Net force
approaches zero = terminal velocity between 120 & 180 mph
III.
Rip cord pulled
A. Chute increases cross-sectional
area =larger frictional force
C. Net force
upward – positive acceleration
IV.
As parachutist slows down frictional force decreases
A. Frictional force approximately
equals force of gravity 5
B. New terminal velocity reached
C. Smaller
terminal velocity because of larger cross-sectional area
D. Person
continues at constant velocity till hits ground,
V.
Ground exerts upward force on person and stops motion
Parachutes
and Terminal Velocity
-- Questions
and Problems
1. What two forces act on the
parachutist during the jump?
2. How do each of these forces
change during the jump?
3. What happens to the net force
while the jumper is in free fall?
4. What is "terminal
velocity" and what causes it?
5.
Why does the downward velocity of a parachutist decrease after the parachute
is opened?
6. Why does a parachutist reach a
second terminal velocity?
7.
Trace what happens to the velocity during the entire jump including: the
initial moment in the air, the free fall, the chute opening, falling the rest
of the way to the earth, and finally, hitting the earth.
8.
When you ride a bicycle down a hill, you will eventually reach a terminal
velocity. If the hill is not very steep, the velocity will be low; a steeper
hill will have a higher terminal velocity. Why does this terminal velocity
occur?
9. A feather reaches a terminal
velocity very quickly. Explain why this happens.
10.
The volcanic explosion of Mt. St. Helens sent dust up into the stratosphere,
which lies more than 7 miles above the surface of the earth. These particles
will stay there for a number of years before falling to earth. They fall to
the earth because of gravity, but why do they take so long to do so?
parts
of above © 1985 J. Weston Walch, Publisher
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Page Last Updated: Saturday June 27, 2009 Webmaster: Larry Jones Pickens County School District |