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Metric System
Metric Prefixes -Dimensional Analysis

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Metric Prefixes

bulletDimensional Analysis Examples
bulletMetric Problems
bulletSI Metric Appendix

 

In 1960 the International Bureau of Weights and Measures (Sevres, France) adopted the "International System of Units", also known as "SI" units.

7 base units are used.  All other SI units are derived from combinations of these base units:
length:   meter (m)
mass:   kilogram (kg)
time:   second (s)
electric current:  ampere (A)
temperature:  kelvin (K)
amount of substance:  mole (mol)
luminous intensity: candela (cd)

General Punctuation Rules:
a) use space instead of comma to separate numbers into groups of three
     ex:    63 000 000 m                0.000 000 003 m

b) use decimals instead of fractions to express partial units

c) space between the numeric value and unit symbol

d) do not use periods after symbols

e) all abbreviations are singular

f) follow capitalization rules as given in problems

 

The following  pages reproduce a portion of the software program available to students. They demonstrate how to use metric prefixes, complete dimensional analysis problems, and reviews SI metrics.  Please read each screen carefully.  You might want to make notes.  Additional problems are available from Mr. Jones.

Metric Prefixes are combined with a unit to indicate that the unit has been multiplied by a certain power of 10.  Prefixes are to be used to keep numerical values in tables, results,  and specifications between 0.1 and 1000.

example:  144 000 N  =  144 kN

Six basic prefixes are used commonly.  They will be used to demonstrate the basic principles.  Less common prefixes are given in the metric appendix.

The first example:  kilo  (abbreviated with lowercase 'k'
This prefix represents 3 decimal places, usually associated with 1000.
examples:  1 km  =  1000 meters  (1000 m)         2.3 kJ  =  2 300 Joules  (2 300 J)

Another example:  centi   (abbreviated with lowercase 'c'
This prefix represents 2 decimal places, usually associated with 0.01
examples:  100 cm  =  1 meter   (1 m)        2.3 E 2 cm  =  2.3 meters (2.3 m)

Another commonly used metric prefix is milli   ('m')
examples:  1000 mL  =  1 liter  (1 L)      2.3 E 3 mL   =   2.3 liters    (2.3 L)

Less common but used occasionally are the following:
mega  ('M')  1 000 000  (1 E 6)
micro   ('µ')   0.000 001  (1 E - 6)
nano   ('n')    0.000 000 001  (1 E - 9)

The remaining prefixes and their multiplication factors can be seen in the metric appendix.

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Dimensional Analysis Examples

Dimensional analysis is also called the factor-label method of problem solving.  It is a way of setting up a problem in a constant fashion that breaks the problem down into simple steps.  Each step is a ratio that must equal 1, thus canceling out some preceding unit.  

example problem:    4.4 km  =  ?  m
solution:   4.4 km  x    1000 m  =  4 400 m
                                    1 km                
(note that the 'km' cancel and you multiply  4.4  times 1000 to get your answer)

 

problem:    4.4 km  =  ? cm
solution:    4.4 km  x  1000 m   x   100 cm    =   4.4 E 5 cm
                                   1 km            1 m

solution using scientific notation:     4.4 km  x  1 E 3 m   x  1 E 2 cm   =   4.4 E 5 cm
                                                                            1 km           1m

problem without metric prefixes:    4.4 weeks  =  ? seconds
solution:   4.4 wk  x  7 day   x  24 hour   x 60 minute    x   60 seconds    =    2.7 E 7 s
                                1 wk          1 day       1 hour             1 minute

some points of interest:

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1 E 3 m = 1 km   

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place the 1 with the large unit (then all other numbers in conversion are greater than 1)

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use base units whenever possible

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must know number of decimal places in each prefix 

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metric problems:  the following problems solutions are part of the homework.  Try them before you look at the solutions (no peeking).  see solutions

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4 g to cg

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12 L to mL

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12. 5 mL to µL

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0.068 kL to L

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8.5 E - 5 mg to cg

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1.85 E - 6 Mm to nm

 

 

 

 

 

 

Solutions:

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4 g  x  1 E 2 cg  =  4 E 2 cg
           1 g

 

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12 L   x    1 E 3 mL   =   1.2 E 4 mL
                 1 L
 

 

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12.5 mL   x        1 L         x   1 E 9 µL     =   1.25  E 7 µL
                       1 E 3 mL          1 L

 

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0.068 kL   x   1 E 3 L     =   68 L
                      1 L

 

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8.5  E - 5 mg    x     1 g        x     1 E 2 cg    =   8.5 E - 6 cg
                           1 E 3 mg             1 g

 

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1.86 E - 6 Mm    x     1 m       x     1 E 9 nm    =    1.86 E - 3 nm
                             1 E 6 Mm           1 m

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Metric Appendix

 


                

 

 

Page Last Updated: Friday March 02, 2007           Webmaster: Larry Jones                 Pickens County School District