Viscosity
Lab Objective: to determine the viscosity of Karo syrup
Theory: An object falling through a viscous medium
will reach a terminal velocity (constant velocity, no acceleration) when the
sum of the buoyant force and the viscous force equals the force of
gravity. For a sphere of radius (r) in a
fluid of density (ρ),
Fbuoyancy +
Fviscosity = Fgravity
Fb =
4/3 π r3 ρ g Fv = 6
π η r vt Fg = m g
where
vt
is the terminal velocity and η is the viscosity. g is given as 980.7
cm/s2
Procedure:
1. Determine the density of the Karo syrup (g/cm3). Record this and the temperature of the
syrup (°C).
2. Measure the diameter of the ball bearing and a marble. Record diameter of each type in cm.
3. Find mass of ball bearing and average mass of
marbles. Record in grams.
4. Using the masking tape, mark off center 50. cm section of plastic tubing (between stoppers). Make certain there is
50. cm between inside portions of tape markers. MAKE CERTAIN THE BOTTOM STOPPER IS INSERTED
TIGHTLY. Angle tubing at a 45° and add
syrup to a height 2 cm above the top masking tape marker. Try to add the syrup so that no bubbles form
in the column by pouring it down the side of the tube. Place tube upright in clamps.
5. Practice dropping and timing the ball bearing
as it falls through the column. You must
start timing when the center of the ball appears under top piece of tape and
stopping when the center of the ball passes behind the bottom piece of
tape. Use the magnet to lift the bearing back to the
top of the syrup column. Repeat 10 times
and record all fall times. This time
will allow you to calculate the velocity of the marble. Velocity is defined as distance traveled (50.
cm here) divided by the time taken (your average of the ten trials). Next drop the ten glass marbles and record
the time for each. Calculate the average
terminal velocity of the glass marble as well.
6. Using the formula: Fbuoyancy + Fviscosity
= Fgravity solve for the
viscosity of the syrup first using your terminal velocity average for the ball
bearing and then for the glass marbles.
Final formula
registration: 4/3 π r3 ρ g + 6 π η r vt = m g
7. Compare the viscosities you just found
(percent difference formula).
8. Compare the average of the two viscosities
with the known value for Karo syrup (using percent
error formula).
Report should
include all data in clean, tabular format along with all mathematical
work. Show all your set-up work, with
units, to receive credit. Place final
viscosities along with percent difference and percent error in a table as
well. Bonus credit is available for
working viscosity with volcanoes problems (required in Honors).
Viscosity
Notes
Viscosity is an internal property of a
fluid that offers resistance to flow. For example, pushing a spoon with a small
force moves it easily through a bowl of water, but the same force moves mashed
potatoes very slowly. In fact, one of the major differences between styles of
mashed potatoes is the viscosity of the starchy mass: some people like their
potatoes running and teeming with milk and butter (they are fans of low‑viscosity
potatoes), while others like their potatoes drier and stickier, so they almost
crack rather than flow (these people are devoted to high‑viscosity
potatoes).
There are many ways to measure
viscosity, including attaching a torque wrench to a paddle and twisting it in a
fluid, using a spring to push a rod into a fluid, and see how fast a fluid
pours through a hole. We will see how fast a sphere falls through a fluid. The
faster the sphere falls, the lower the viscosity. If the fluid has a high
viscosity it strongly resists flow, so the sphere falls slowly. If the fluid
has a low viscosity, it offers less resistance to flow, so the ball falls
faster.
Theory:
An object falling through a viscous medium will reach a terminal
velocity (constant velocity, no acceleration) when the sum of the buoyant force and
the viscous force equals the force of gravity.
For a sphere of radius (r) in a fluid of density (ρ),
Fbuoyancy + Fviscosity = Fgravity
Fb
= 4/3 p r3 ρ g Fv = 6
p η r vt Fg = m g
where vt is the terminal velocity and η is the
viscosity. g
is given as 9.807 m/s2
Alternate formula:
Viscosity (É) = 2(¥Ó) g a2 / 9 v
where = ¥Ó = difference in density
between the sphere and the liquid, g = acceleration of gravity, a = radius of
sphere, and v = velocity (d/t)
Viscosity can be measured in
different unit systems. The SI unit is N s/m2 which is known as the poiseuille (PI). An older unit, the poise (dyne s/cm2)
remains in common use (where 10 poise = N s/m2
and 100 centipoise = 1 poise) (1 Pa s or Pascal
second is also used).
In order to understand what
viscosity is, you need to realize that it is the ratio of the shear force applied
and the amount of resulting deformation. The deformation of the fluid is
expressed as the rate of shear. Therefore, viscosity is the relationship
between shearing stress and rate of sheer.
In the simplest cases, like water
or aqueous solutions, the shearing stress is directly proportional to the rate
of shear. The proportionality constant is called the viscosity coefficient or
the viscosity of the liquid. Fluids where the proportion is direct are called
Newtonian.
Newtonian and Non-Newtonian Fluids
Fluids, including finished beverages,
are either Newtonian or Non‑Newtonian. The simplest are the Newtonian
ones, like water, dilute suspensions, aqueous solutions, and emulsions.
Viscosity is temperature dependent and typically decreases as the temperature
rises. Other examples of Newtonian fluids include some motor oils, most mineral
oils, gasoline, kerosene, most salt solutions in water.
Non‑Newtonians are a group
of liquids that change viscosity when they are stirred, shaken, or otherwise
agitated.
Ketchup becomes thicker, or more
viscous, when it sits still. If you stir it up or shake it, it becomes thinner,
or less viscous. Ketchup is a thixotropic liquid. It
becomes less viscous when agitated. It is similar to Visplex
(a drilling fluid). This fluid is a liquid while in motion, but when at rest it
turns into a thick gel. This makes it useful because when the circulation of
the drilling fluid stops, the gel suspends the rock cuttings and prevents them
form sinking to the bottom of the borehole. Other thixotropic
liquids include most paints, silica gel, greases, inks, milk, mayonnaise,
asphalt, glues, molasses, starch, lard, and fruit juice concentrates). Theory:
Ketchup that has been standing still is thicker (more viscous) than ketchup
that has been stirred or shaken. Part of this comes from the nature of the
macerated tomatoes. The solid part of the fruit must form suspended microfibers when ground up. On standing still the fibers in
such a suspension increasingly make contact with each other and stick together.
This forms a 3‑D structure or gel throughout the fluid, the strength of
which increases with time. The gel structure is broken by agitation, reducing
the viscosity. Ketchum also contains xanthan gum, a
thickener. This gum dissolves in water to form a thixotropic
gel. The gum polymer molecules are very much smaller. The rod‑like
polymer molecules also build a structure with time. There may also be some gels
arising from pectin if there is any in the tomato paste. Pectin is also a
soluble polymer that has the power to form a cross‑linked gel with
sugars.
Another non‑Newtonian liquid
is a mixture of cornstarch and water. It also acts differently depending on
whether it is still or agitated. But the behavior is the opposite of ketchup.
This kind of fluid is called dilatant. It becomes
more viscous when agitated or compressed.
Theory: To start thinking about
why the cornstarch and water mix behaves the way it does it may help to realize
that it is not a simple liquid like water, oil, or corn syrup. It is a
suspension. The tiny granules of cornstarch do not dissolve in the water.
Rather they are mixed in with the water but remain intact and solid. In a salt
water mixture, the salt dissolves in the water. There are no chunks of salt
floating around.
The most generally accepted
explanation for the behavior of the cornstarch water mix is that when sitting
still the granules of starch are surrounded by water.
The surface tension of the water keeps it from completely flowing out of the
spaces between the granules. The cushion of water provides quite a bit of
lubrication and allows the granules to move freely. But, if the movement is
abrupt, the water is squeezed out from between the granules and the friction
between them increases rather dramatically.
Another possible explanation:
Cornstarch molecules are in long chains called polymers that get stretched when
the mixture is compressed. They may also get tangled so as not to slide easily
against each other. It would make sense that stretched fibers would offer more
resistance to movement, just like the resistance of a taut rubber band or a
coil spring under tension. But the tangling argument doesn't explain why rapid
motion increases viscosity. Wouldn't the fibers be tangled when the mixture is
moving slowly or still? In fact, rapid motion might break the fibers. Another
problem with this model is that the starch is not separated into molecules, but
rather exists as much larger granules, which are essentially spherical. These
granules will dissolve with heat. A cornstarch and water mixture pouted into a
sauce during cooking will thicken it. This will only happen if the sauce is
hot. We should also note that a mixture of find sand and water exhibits
behavior similar to the cornstarch and water mix, but sand molecules are not
polymers. Static electricity has also been presented as a possible explanation.
The first explanation seems to be
the most convincing. The starch granules are monodisperse,
meaning that they are all about the same size. This is known to increase dilatancy, perhaps allowing more rapid drainage of water on
pressing that would be case with polydisperse (broad
particle size distribution) particles which can pack together more closely.
Other dilatant
mixtures: starch in water, beach sand, quick sand, candy compounds, peanut
butter.
To summarize:
thixotropic = viscosity decreases as stress
increases, but, given time, returns to original.
dilatant = viscosity decreases non‑proportionally
as the shearing stress and rate of shear increase
Thanks to an excellent web site produced
by the SEED Foundation (www.slb.com/seed/) for
the above information. The web page dealing with the above information on
viscosity is: http://www.seed.slb.com/en/scictr/lab/viscosity/
found on the SEED web site. They also have virtual a viscosity experiment
at http://www.slb.com/seed/en/lab/visco_exp/index.htm.
Viscosity is important in volcanology.
The more fluid a magma, the more likely it is to erupt. On the other hand, when
more viscous (higher viscosity) lavas do erupt, they usually do so explosively.
Viscosity also affects the shapes of lava flows and the mountains they erupt
from. The more viscous the magma, the fatter the lava flow.
Also, the more viscous the magmas a volcano erupts, the steeper the volcano.
Thus, shield volcanoes like we have in
Viscosity Calculations:
Jefferys (1925) derived a formula to calculate the viscosity of a fluid based on its physical properties and flow characteristics. The formula is:
V = g h2 Ó sin A
3 É
where V is the mean velocity of the flow, g is the coefficient of gravity (9.807 m/s2), A is the angle of the slope, h is the depth of the flowing liquid, Ó is the density of the liquid (cool, basaltic rock has a density of 2.65 g/cm3 so the hot, basaltic lava must be less than this ‑ MacDonald used a value of 2 g/cm3), and É is the coefficient of viscosity (É is the Greek letter eta).
MacDonald (1954) calculated the viscosity of lava
during
Use MacDonald's estimates and the equation to calculate the viscosity. The units for viscosity used by MacDonald are poises. A poise is 1 g/an s. Therefore, to make the calculations, all measurements must be converted from meters to centimeters.
|
Date |
Location
|
Speed (m/s) |
Lava depth (m) |
Slope angle |
Viscosity (poise) |
|
4/ 12/40 |
Side of cone at vent |
6.7 |
1 |
20 |
|
|
|
Edge of core at vent |
8.3 |
2 |
6 |
|
|
|
cascade 0.6 km from vent |
13.3 |
2 |
15 |
|
|
|
Entire Honokua
flow |
2.7 |
2 |
10.5 |
|
|
|
Cascade in Kaapuna flow 20 km from vent |
11.1 |
2 |
17.5 |
|
|
|
Lava river in Kaapuna
flow 20.5 km from vent |
6.9 |
3 |
8 |
|
|
|
cascade cose
to vent |
13.9 |
1.5 |
25 |
|
Based on your calculations, answer the following questions:
1. Which eruptions had the lowest viscosities?
2. Why are the viscosities low for these eruptions?
3. Which eruptions had the highest viscosities?.
4. Why is the viscosity high for these eruptions?
5. In general, do the estimates show that viscosity increases with distance from the vent?